(Q4).Check whether 301 is a term of the list of numbers 5, 11, 17, 23, . . .

We have

a2 – a1 = = , a3 – a2 = = , a4 – a3 = =

As (ak+1 – ak) is the same for k = 1, 2, 3, etc., the given list of numbers is an AP

Now, for this AP we have a = and d =

We choose to begin with the assumption that 301 is nth term of the this AP. We will see if an ‘n’ exists for which an = 301

We know

an = a + (n – 1) d

So, for 301 to be a term we must have

= + (n – 1) ×

or = n –

So, n =
=

But n should be a positive integer.

So, 301 is not a term of the given list of numbers.