Here, a = , d = – = – , l = –

where l = a + (n – 1) d

To find the 11th term from the last term, we will find the total number of terms in the AP

So, – = + (n – 1)(–)

i.e., – = (n – 1)(–)

i.e., n – 1 =

or n =

So, there are terms in the given AP

The 11th term from the last will be the 15th term of the series. (Note that it will not be the 14th term. Why?)

So, a₁₅ = + ( – 1)(–) = – = –

i.e., the 11^th term from the end is – .