(Q6).Find the sum of :

(i) the first 1000 natural numbers

Let S = 1 + 2 + 3 + . . . + 1000

Using the formula Sn =
n
2
(a + l) for the sum of the first n terms of an AP, we have
Sn =
2
( + ) = × =

So, the sum of the first 1000 positive integers is .