Given G.P.: 2, 8, 32,….. is 512
Let the nth term of G.P. be 512
an = a.rn-1
= × ()n-1
9 = × (2)n-1
9 = 1 × 2(n-1)
9 = 2n-2+1
9 = 2n-1
512 = × × × × × × × ×
= 9
∴ n – 1 =
[∵ bases are equal, exponents are also equal]
∴ n = + 1 =
∴ 512 is the th term of the given G.P.