(Q11).Which term of the G.P.

(ii).√3, 3, 3√3, …….. is 729?

Given G.P.: √3, 3, 3√3, …….. is 729

a = √, r =
a2
a1
 =
√

now an = a.rn-1 = 729

⇒ (√)(√)n-1 = 729

⇒ (√)n = 6 = (√)12

⇒ n =

So th term of GP √3, 3, 3√3, …….. is 729.