(Q2).Which term of the GP : 2, 2√2, 4 ..... is 128 ?

Here a = , r =
√2
= √

Let 128 be the nth term of the GP

Then an = a.rn-1 =

.(√)n-1 =

(√)n-1 =

()
n-1
2
= 6
n-
=

∴ n = .

Hence 128 is the th term of the GP