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(Q3).In a GP the 3^rd term is 24 and 6^th term is 192. Find the 10^th term.

Here a₃ = ar² = 24 ...(1)

a₆ = ar ⁵ = 192 ...(2)

Dividing (2) by (1) we get

ar⁵

ar²

=

⇒ r³ = = ³

⇒ r =

Substituting r = in (1) we get a =

∴ a₁₀ = ar ⁹ = ()⁹ = .