(Q20)Do the points (3,2),(-2,-3) and (2,3) form a triangle?

Answer

Let us apply the distance formula to find the lengths PQ,QR, and PR, where P(3,2),Q(-2,-3) and R(2,3) are the given points.We have

PQ=√((--)2 + (--)2)

=√((-)2 + (-)2)

=√

=.07units(approx)

QR=√((-(-))2 + (-(-))2)

=√(2 + 2)

=√

=.21units(approx)

PR=√((-)2 + (-)2)

=√((-)2 + 2)

=√

=.41units(approx)

Since the sum of any two of these lengths is greater than the third length, the points P,Q and R from a triangle and all the sides of triangle are unequal.