Let A(1,7) B(4,2) , C(-1,-1) and D(-4,4) be the given points.
On way of showing that ABCD is a square is to use property that all its sides should be equal and both its diagonals should also be equal.Now the sides are
AB = √(( - )2 + ( - )2) = √ units
BC = √(( + )2 + ( + )2) = √ units
CD= √((- + )2 + (- - )2) = √ units
DA = √((- - )2 + ( - )2) = √ units
and diagonal are
AC = √(( + )2 + ( + )2) = √ units
BD = √(( + )2 + ( - )2) = √ units
Since AB = BC = CD = DA and AC = BD. So all the four sides of the quadrilateral ABCD are equal and its diagonals AC and BD are also equal. Therefore ABCD as a square.