(Q25)Find the distance between the following pair of points
(i)(2,3) and (4,1) (ii)(-5,7) and (-1,3) (iii)(-2,-3) and (3,2) (iv)(a,b) and (-a,-b).

Answer

(i)Distance= √((x2 - x1)2 + (y2 - y1)2)

= √((-)2 + (-)2)

= √

= √2 units

(ii)Given (-5,7) and (-1,3)

Distance= √((x2 - x1)2 + (y2 - y1)2)

= √((--)2 + (-)2)

= √

= √2 units

(iii)(-2,-3) and (3,2)

Distance= √((x2 - x1)2 + (y2 - y1)2)

= √((+)2 + (+)2)

= √

= √2 units

(iv)(a,b) and (-a,-b)

Distance= √((x2 - x1)2 + (y2 - y1)2)

= √((--)2 + (--)2)

= √(42 + 42)

= √4(2+2)

=2 √(2 + 2)