Let A=(5,-2);B=(6,4) and C=(7,-2)
Distance =√((x2 - x1)2 + (y2 - y1)2)
AB=√((-)2 + (+)2)
=√
BC=√((-)2 + (--)2)
=√
AC=√((-)2 + (-+)2)
=√
Now we have, AB=BC
∴ triangle ABC is an isosceles triangle,
∴ given points are the vertices of an isosceles triangle.