Answer

Given p(2,-3),Q(10,y) and PQ=10.

Distance formula=√((x₂ - x₁)² + (y₂ - y₁)²)

√((-)² + (y+3)²) = 10

√(y² + 6y + ) = 10

Squaring on both sides we get

y²+6y+=100

y²+6y-=0

y²+9y-y-=0

y(y+9)-(y+9)=0

(y+9)(y-)=0

y+9=0 or y-=0

y= -9 or