(Q38)Can you draw a triangle with vertices (1,5),(5,8) and C(13,14)? Give reason.

Answer

Let A(1,5), B(5,8) and C(13,14) be the given points.

Distance formula = √((x2 - x1)2 + (y2 - y1)2)

AB=√((-)2 + (-)2)

=√

=

BC=√((-)2 + (-)2)

=√

=

AC=√((-)2 + (-)2)

=√

=

Here AC=AB+BC

Triangle ABC cant be formed with the given vertices.