(Q27) Find the coordinates of a point A, where AB is the diameter of a circle whose center is(2,-3) and B(1,4).

Answer

ABC(2,-3)(1,4)

Given: A circle with center 'C' (2,-3).AB is a diameter where,

B=(1,4);A=(x,y)

C is the mid point of AB.

[Center of a circle is the midpoint of the diameter]

Midpoint = (
x1+x2
2
 ,
y1+y2
2
)
(2,-3)= (
x+
2
 ,
y+
2
)
2=
x+
2
 and -3=
y+
2

4=x+ and -6=y+

x=4- = and y= -6- = -

A(x,y)=( ,- ).