(Q11) Find the area of square formed by (0,-1) , (2,1) , (0,3) and (-2,1) taken in order are as vertices.

ABCD(0,-1)(2,1)(0,3)(-2,1)

Let A (0,-1) , B (2,1) , C(0,3) and D(-2,1) are the vertices of the square.

Area of the square ABCD = side2 = AB2

But AB = √((x2 - x1)2 + (y2 - y1)2)

       = √(( - )2 + ( + )2)

       = √

Area of the square = √ × √.

= sq.units .