(Q12) Find the area of the triangle formed by the following points .

(i) (2,0) , (1,2) , (1,6)    (ii)(3,1) , (5,0) ,(1,2)    (iii) (-1.5,3) , (6,2) , (-3,4)

(i) Take the third point as (-1,6)

∆ =
1
2
 |x1(y2 - y3)+ x2(y3 - y1) + x3(y1 - y2)|
∆ =
1
2
 |2( - )+1( - ) - 1( - )|
  =
1
2
 || =

(ii) (3,1) , (5,0) , (1,2)

∆ =
1
2
 |3(-)+5(-)+1(-)|
 =
1
2
 || =

(iii) (-1.5,3) , (6,2) ,(-3,4)

take the second point as (6,-2)

∆ =
1
2
 |-1.5(- - )+6(-) - 3( - (-))|
 =
1
2
 |+-| =
1
2
 || =