(Q21) Find the area of the triangle whose vertices are (-5,-1) , (3,-5) , (5,2).
Given : A(-5,-1) , B(3,-5) and C(5,2) are the vertices of ∆ABC
Area of the ∆ABC,
=
1
2
|x
1
(y
2
-y
3
)+x
2
(y
3
-y
1
)+x
3
(y
1
-y
2
)|
=
1
2
|-5(-
-
)+3(
+
)+5(-
+
)|
=
1
2
|
|
=
2
=
sq.units .
Clear