(Q22) Find the area of the triangle whose vertices are (0,0) , (3,0) , (0,2).
Given : O(0,0) , A(3,0) and B(0,2) are the vertices of triangle ,∆AOB
Area of the AOB,
=
1
2
|x
1
(y
2
-y
3
)+x
2
(y
3
-y
1
)+x
3
(y
1
-y
2
)|
=
1
2
|0(
-
)+3(
-
)+0(
-
)|
=
1
2
|
|
=
sq.units.
Clear