(Q8) Find the area of the triangle whose vertices are (5,2) (3,-5) and (-5,-1).
Given the vertices of the triangle are (5,2) , (3,-5) and (-5,-1).
Area of the triangle,
∆ =
1
2
|x
1
(y
2
- y
3
)+x
2
(y
3
- y
1
)+x
3
(y
1
- y
2
)|
∆ =
1
2
|5(-
-(-
))+3((-
)-
)+(-5)(
-(-
))|
=
1
2
|5×(-
)+3×(-
)+(-5)×
|
=
1
2
|-
| =
2
=
sq.units
Clear