(Q1)Center of the circle Q is on the Y-axis and the circle passes through the points (0,7) and (0,-1). Circle intersects the positive X-axis at (p,0).What is the value of 'p'.

A (0,7)Q(0,3)B(0,-1)

Given points A,B are only on y-axis

(their x-coordinates is zero ) then they will be the end points (0,7) and (0,-1)

Center (Q) = (
+
2
 ,
-
2
 ) = (,)

Then radius = AQ = BQ

= √(( - )2+( - (-))2)

=√(2+2) = √

=

now P(p,0) is also another point on circle then QP is also radius

QP = √(( - p)2+( - 0)2) =

√(p2+2) =

p2 = 2 - 2 = - =

P = ±√