(Q12) In the given figure LM ∥ AB, AL = x - 3, AC = 2x, BM = x - 2 and BC = 2x + 3 find the value of x.
Solution :
A
B
C
M
L
In ∆ABC, LM ∥ AB
AL
LC
=
BM
MC
(By B.P.T)
2x - (x - 3)
=
(2x + 3) - (x - 2)
=
(cross multiplication)
(
)(
) = (
)(
)
x
2
+ 2x - 15 = x
2
+ x - 6
2x - x = - 6 + 15
∴ x =
clear