(Q14) In △ABC, DE || BC. AD = x, DB = x - 2, AE = x + 2 and EC = x - 1. Find the value of x.

Solution :

Given :In △ABC, DE ∥ BC

∴ By Basic proportionality theorem, we have

⇒ x (x - 1) = (x + 2)(x - 2)

⇒ x² - x = x² - 4

⇒ =

∴ x =