Solution :
Given :In ∆PQR, AB ∥ PQ; AC ∥ PR
R.T.P : BC ∥ QR
Proof : In ∆POQ, AB ∥ PQ
(∵ Basic Proportional theorem)
and in ∆OPR,
From (1) and (2), we can write
Then consider above condition in ∆OQR then from (3) it is clear.
∴ BC ∥ QR [∵ from converse of Basic Proportionality Theorem]
Hence Proved.