(Q8) E and F are points on the sides PQ and PR respectively of △PQR. For each of the following, state whether EF || QR or not ?

iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 1.8 cm and PF = 3.6 cm.

Solution :

Given :PQ = cm, PE = cm

⇒ EQ = PE - PQ = -

⇒ EQ = cm

Also, PR = cm, PE = cm, FR = PF - PR = cm - cm

FR = cm

∴ EF ∥ QR (By converse of Basic proportionality theorem)

Hence, EF is parallel to QR.