Solution :
Steps of construction:
1. Draw ∆ABC in which BC = 8 cm and altitude AD = 4 cm.
2. Draw a ray making an acute angle with BC on the side opposite to vertex A.
3. Mark three points B1, B2 and B3 such that BB1 = B1B2 = B2B3.
4. Join B2C.
5. Draw a line parallel to B2C through B3 meeting produced at C'.
6. Draw a line parallel to through C' meeting BA produced at A'.
7. ∆A'BC' is the required triangle.