Schoolcrop

Solution:

Given : ∆ABC ∼ ∆DEF

BC = 3 cm

EF = 4 cm

∆ABC = 54 cm²

∴ ∆ABC ∼ ∆DEF, we have

∆ABC

∆DEF

BC²

EF²

[∵ The ratio of two similar triangles is equal to the ratio of the squares of the corresponding sides].

∆

∴ ∆DEF =

= cm²

(Q7) ∆ABC ∼ ∆DEF. BC = 3 cm, EF = 4 cm and area of ∆ABC = 54 cm2. Determine the area of ∆DEF.