Solution :
Let l, m, n are integer sides of a angled triangle.
then l2 = m2 + n2
⇒ n2 = l2 - m2 = (l + m) (l - m)
Now,
Case I :
Both l,m are even the (l + m) is even then (l + m) (l - m) is also even. So 'n' is even. Here all are .
Case II :
Both l, m are odd then (l + m) and (l - m) become even. Then the product of even numbers is even so 'n' is .
Here only 'n' is .
Case III :
If we consider l is even, m is' odd then 'n' will be odd. So here T is even. We observe in all above three cases at least one of l, m, n is ;
Hence Proved