Solution :
Let A and D be the windows on the either sides of the street.
AC2 = AB2 + BC2
( )2 = ( )2 + BC2
BC2 = -
BC = √( ) = ( ) .....(1)
Also, CD2 = DE2 + CE2
( )2 = ( )2 + CE2
CE2 = -
CE = √( ) = ( )
∴ BE = BC + CE = + =
Width of the street = m.