(Q5)Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and ∠B = 90°. BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.

Steps of construction

  1. Draw ABC such that AB = cm;∠B = ° and BC= cm
  2. Drop a perpendicular BD from B on AC
  3. Draw the circumcircle to ABCD. Let '' be its center
  4. Join AE and draw its perpendicular bisector XY. Let it meet AE at
  5. Taking M as center and MA or ME as radius draw a circle, which cuts the circumcircle of triangle BCD at P and B
  6. Join AP and extend AB, which are the required tangents