(Q8) Find the length of the tangent to a circle with center 'O' and radius= 6cm. form a point P such that OP=10cm

Tangent is perpendicular to the radius at the point

Here PA is tangent segment and OA is radius of circle

APO106

OA ⟂ PA

∠OAP = 90°

Now in Triangle OAP, OP2 = OA2+ PA2 (pythagoras theorem )

OP2 = OA2+PA2

2 = 2+PA2

= +PA2

PA2 = -

  =

PA = √ = cm