(Q13) In figure OACB is a quadrant of a circle with center O and radius 3.5 cm.If OD = 2cm.Find the area of the shaded region,(use π)

Given , OACB is a quadrant of a circle

Radius = 3.5cm; OD = 2cm

Area of the shaded region = Area of the sector - Area of triangle BOD

=
x
360
 ×πr2 -
1
2
 ×OB×OD
=
360
 ×
22
7
 × × -
1
2
 ××
=
1
 ×
22
7
 × -

= .625 - = .125 cm2

Area of shaded region = .125 cm2