(Q8) A chord of a circle of radius 10 cm.subtends a right angle at the center. Find the area of the corresponding (useπ value)

(i)Minor segment  (ii) Major segment

PQO10cm10cm

Angle subtended by the chord = 90° Radius of the circle = 10 cm

Area of the minor segment = Area of the sector POQ - Area of triangle POQ

Area of the sector =
x
360
 × πr2
360
 ×3.14×10×10 = .5
Area of the triangle =
1
2
 ×base×height
        =
1
2
 ×× =

Area of the minor segment = .5 - = .5cm2

Area of the major segment = Area of the circle - Area of the minor segment

= 3.14×10×10 - .5

= 314 - .5 cm2

= .5cm2